The value of $V_{0}$ in the given diagram is

4 V

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6 V

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8 V

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10 V

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Solution

The correct option is C $8 V$
Let the current in $O A$ , $O B$ and $O C$ be $I_{1}$ , $I_{2}$
and $I_{3}$ respectively and direction of all the three currents
be towards $O$ .
Applying Kirchoff's law at $O$ :
$I_{1}$ + $I_{2}$ + $I_{3}$ = $0$
$\frac{V_{0} - 10}{10}$ + $\frac{V_{0} - 6}{20}$ + $\frac{V_{0} - 5}{30}$ = $0$
$\frac{6 (V_{0} - 10) + 3 (V_{0} - 6) + 2 (V_{0} - 5)}{60}$ = $0$
$V_{0}$ = $8$ V .

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