The value of [→a−→b→b−→c→c−→a] where |→a|=1,|→b|=5,|→c|=3, is
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
Since,→a−→b+→b−→c+→c−→a=0, therefore the vectors →a−→b,→b−→cand→c−→a are coplanar. We know that if three vectors are coplanar, then their box product would be equal to zero. Also try to recollect why this is so. Hence for our present case, [→a−→b→b−→c→c−→a]=0.