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Question

The value of [ab bc ca] where |a|=1,|b|=5,|c|=3, is

A
1
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B
6
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C
None of these
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Solution

Since,ab+bc+ca=0, therefore the vectors
ab,bc and ca are coplanar. We know that
if three vectors are coplanar, then their box product would be equal to zero. Also try to recollect why
this is so.
Hence for our present case, [ab bc ca]=0.

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