The value of (x+2y)3 is _______.
x3+8(y)3+6x2y+12xy2
x3−8(y)3+6x2y−12xy2
x3+8(y)4+6x2y+17xy2
(2x)3+8(y)3+6x2y+12xy2
(x+2y)3
Use the formula : (a+b)3 = a3+b3+3a2b+3ab2
Here, a = x and b = 2y
(a+b)3 = (x+2y)3 = x3+(2y)3+3x2(2y)+3x(2y)2
= x3+8(y)3+6x2y+12xy2
Find the cube of x+2y.