Question

The value of $x$ for which $\frac{x-3}{4}--x<\frac{x-1}{2}-\frac{x-2}{3}$ and $2-x>2x-8$

• A. $[-1,10/3]$
• B. $(1,10/3)$
• C. $R$
• D. none of these

Answer 1

The correct option is A $[-1,10/3]$

$\frac{x-3}{4}-x<\frac{x-1}{2}-\frac{x-2}{3}$

$\frac{-3x-3}{4}<\frac{x+1}{6}$

$⟹x>-1$

$2-x>2x-8⟹x<\frac{10}{3}$

$⟹x\in (-1,10/3)$