The value of x for which $c o s^{- 1} (c o s 4) > 3 x^{2} - 4 x$ is

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(-2, 2)

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Solution

The correct option is D

$c o s^{- 1} (c o s 4) = 2 π - 4$
$π - 4 > 3 x^{2} - 4 x$
$\Rightarrow 3 x^{2} - 4 x - 2 π - 4 < 0$
$\Rightarrow \frac{2 - \sqrt{6 π - 8}}{3} < x < \frac{2 + \sqrt{6 π - 8}}{3}$

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