The value of x- for which the functions fx-x- gx-x2 and hx-x2-x are identical- is A- 0- xB- All real valuesC- All real values except 0 D- 0 - x

The correct option is A 0 lt; xAll three functions would give the same values for x gt; 0. As g(x) is not defined for negative x, and h(x) is not defined ...

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The value of x, for which the functions f(x) = x, g(x) = $(\sqrt{x})^{2}$ and h(x) $= \frac{x^{2}}{x}$ are identical, is

\leq

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0 < x

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All real values

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All real values except 0

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Solution

The correct option is B 0 < x
All three functions would give the same values for x > 0. As g(x) is not defined for negative x, and h(x) is not defined for x = 0.

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The value of x, for which the functions f(x) = x, g(x) = (√x)2 and h(x) =x2x are identical, is

The correct option is B 0 < xAll three functions would give the same values for x > 0. As g(x) is not defined for negative x, and h(x) is not defined for x = 0.

The value of x, for which the functions f(x) = x, g(x) = $(\sqrt{x})^{2}$ and h(x) $= \frac{x^{2}}{x}$ are identical, is

The correct option is B 0 < x
All three functions would give the same values for x > 0. As g(x) is not defined for negative x, and h(x) is not defined for x = 0.