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Question

The value of x, for which the points (x,-1), (2,1) and (4,5) lie on a line is

A
3
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B
2
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C
1
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D

0

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Solution

The correct option is C 1

The condition for the three points to lie on a straight line is that the area of the triangle formed by these three points is zero.
Area of a triangle = 0
12[x1(y2y3)+x2(y3y1)+x3(y1y2)] = 0

x(1 - 5) + 2(5 + 1) + 4 (-1-1) = 0

x - 5x + 10 + 2 - 4 - 4 = 0

-4x + 12 - 8 = 0

-4x+4=0

x=1


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