Question

The value of x from the equation
$\frac{x}{cos{45}^0.sin{60}^0}=ta{n}^2{60}^0-ta{n}^2{30}^0$, is

• A. 3
• B. 2
• C. 1
• D. None of these

Answer 1

The correct option is D None of these

$\frac{x}{cos{45}^{0}sin{60}^0}=ta{n}^2{60}^0-ta{n}^2{30}^0$
$\frac{x}{\frac{1}{\sqrt{2}}\frac{\sqrt{3}}{2}}=3-\frac{1}{3}$
$\frac{2\sqrt{2}x}{\sqrt{3}}=\frac{8}{3}$
$x=\frac{2\sqrt{2}}{\sqrt{3}}$
Hence the answer is D