Question

The value of $x$, if $\Delta ABC$ is a right angled triangle is:

• A. $3$
• B. $12$
• C. $6$
• D. $2$

Answer 1

The correct option is C $6$

Using Pythagoras theorem,
$(2x-2{)}^2=x^2+(x+2{)}^2$
$\Rightarrow 4x^2-8x+4=x^2+x^2+4x+4$
$\Rightarrow 2x^2-12x=0$
$\Rightarrow x(2x-12)=0$

$\Rightarrow x=0,6$

As $x$ cannot be $0$, $x=6$