The value of $x$ if $2^{x} + 2^{x} + 2^{x} = 192$ is

5

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\frac{1}{6}

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6

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None of these

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Solution

The correct option is C $6$
Given, $2^{x} + 2^{x} + 2^{x} = 192$
$\Rightarrow 3 (2^{x}) = 192$
$\Rightarrow 2^{x} = \frac{192}{3}$
$\Rightarrow 2^{x} = 64$
$\Rightarrow 2^{x} = 2^{6}$
$\Rightarrow x = 6$
Option C is correct.

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