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Byju's Answer
Standard VI
Mathematics
Finding Solution of an Equation by Trial and Error Method
The value of ...
Question
The value of
x
in
14
(
x
2
−
2
)
+
4
=
4
is ___________.
A
7
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B
4
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C
14
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D
12
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Solution
The correct option is
B
4
Given,
14
(
x
2
−
2
)
+
4
=
4
⇒
14
(
x
2
−
2
)
=
4
−
4
=
0
⇒
x
2
−
2
=
0
14
=
0
⇒
x
2
=
0
+
2
=
2
⇒
x
=
2
×
2
⇒
x
=
4
Suggest Corrections
0
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