The value of 'x' in "y = -17x + 5" when y = 22 is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D -1
y = -17x + 5

Value of y = 22

Putting this we get,

⇒ 22 = -17x + 5

⇒ 17 = -17x

⇒ x = -1

∴ Value of x = -1

Suggest Corrections

Similar questions

y^{''} (1)

x^{3} - 2 x^{2} y^{2} + 5 x + y - 5 = 0

y (1) = 1

\frac{x}{y} = \frac{13}{6}

(i) \frac{3 x + 5 y}{3 x - 5 y} (ii) \frac{2 x^{2} + 5 y^{2}}{2 x^{2} - 5 y^{2}}

| x - 2 | + | y - 5 | = 4

15 x + 17 y = 21

17 x + 15 y = 11

x + y

x + y = 6, 2 x + y = 4

x + 2 y = 5

Join BYJU'S Learning Program