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Question

The value of x:x2+2x8+x2=0 is ?

A
5
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B
2
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C
2
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D
3
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Solution

The correct option is C 2
Case1:x>0
x2+2x8+x2=0
x2+2x8+x2=0
x2+3x10=0
x2+5x2x10=0
x(x+5)2(x+5)=0
(x+5)(x2)=0
x={5,2}
Case2:x<0
x2+2x8+x2=0
x22x+8+x2=0
x2x+6=0
x2+x6=0
x2+3x2x6=0
x(x+3)2(x+3)=0
(x+3)(x2)=0
x={3,2}
x={5,2}{3,2}={2}

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