Question

The value of $x$ satisfying $\frac{(3y-4)}{3}-\frac{(2y-1)}{5}=-\frac{14}{6}$ is______

Answer 1

$\frac{(3y-4)}{3}-\frac{(2y-1)}{5}=-\frac{14}{6}$

$⟹10(3y-4)-6(2y-1)=-14\times 5$

$⟹30y-40-12y+6=-70$

$⟹18y-34=-70$

$⟹18y=34-70$

$⟹18y=-36$

$\therefore y=-2$