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Question

The value of x satisfying the equation 6xx+42x+4x=11 is

A
435
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B
435
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C
163
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D
None of these.
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Solution

The correct option is D None of these.
6xx+42x+4x=11
For the square roots to exist
xx+40x<4 or x0(1)
x+4x0x4 or x>0(2)
From equation (1) and (2),
x(,4)(0,)

Assuming xx+4=y
The given equation can be written as,
6y2y=116y211y2=0
(6y+1)(y2)=0y=16, y=2y=2 (y=xx+40)
Thus,
y=2xx+4=y2=4x=4x+16x=163
This is a acceptable value of x as x(,4)(0,)

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