The value of x, such that the line through (3,x) and (2,7) is parallel to the line through (−2,3) and (0,5), is
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Solution
Let m1 be the slope of line passing through (3,x) and (2,7) m1=7−x2−3 and m2 be the slope of line passing through (−2,3) and (0,5) m2=5−30−(−2)=22=1 As lines are parallel, so, m1=m2 ⇒7−x2−3=1⇒x=8