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Question

The value of x that satisfies the relation x=1x+x2x3+x4x5+. if |x|<1

A
1±52
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B
1±3i2
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C
0
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D
none
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Solution

The correct option is C 1±52
Here the first term is a
Common ratio is given by x
The sum of infinite series is of an GP is given by a1rx=dfrac11+xx2+x=1x2+x1=0
Using quadratic formulae b±b24ac2a
Here a=1b=1c=1
x=1±1+42x=1±52

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