CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
289
You visited us 289 times! Enjoying our articles? Unlock Full Access!
Question

The value of x that satisfies the relation x=1x+x2x3+x4x5+. if |x|<1

A
1±52
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1±3i2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1±52
Here the first term is a
Common ratio is given by x
The sum of infinite series is of an GP is given by a1rx=dfrac11+xx2+x=1x2+x1=0
Using quadratic formulae b±b24ac2a
Here a=1b=1c=1
x=1±1+42x=1±52

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon