The value of x that satisfies |x−1|=|x+3| is
1
-1
2
-2
Given |x−1|=|x+3| Squaring both sides
(x−1)2=(x+3)2)
x2−2x+1=x2+6x+9
⇒−2x−6x=9−1
⇒−8x=8
⇒x=−1