Question

The value of $x$ which satisfies $\frac{4x}{x^2+1}=\frac{4}{x+2}$ is:

• A. $-\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $0$
• D. $2$

Answer 1

The correct option is B $\frac{1}{2}$

$\frac{4x}{x^2+1}=\frac{4}{x+2}$

$\Rightarrow 4x(x+2)=4(x^2+1)$ .... by cross multiplying

$\Rightarrow 4x^2+8x=4x^2+4$

$\Rightarrow 8x=4$

$\therefore x=\frac{4}{8}=\frac{1}{2}$