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Question

The value of x which satisfies the equation log4+(1+12x)log3=log(x3+27) is

A
xϕ
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B
1
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C
4
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D
none of these
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Solution

The correct option is D none of these
log4+(1+12x)log3=log(x3+27)
log4+log3+log312x=log(31x+27)
log(12.312x)=log(31x+27)[loga+logb+logc=log(abc)]
12.312x=31x+27
Let 312x=y
y212y+27=0y=9 or y=3
x=14 and x=12

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