Question

The value of x (x > 0) for which $\tan \left({\sec }^{-1}\frac{1}{x}\right)=\sin \left({\tan }^{-1}2\right)$ is

x (x > 0) के किस मान के लिए $\tan \left({\sec }^{-1}\frac{1}{x}\right)=\sin \left({\tan }^{-1}2\right)$ है?

• A. $\frac{\sqrt{5}}{3}$
• B. $\frac{1}{2}$
• C. $\frac{2}{\sqrt{5}}$
• D. $\frac{3}{\sqrt{5}}$

Answer 1

The correct option is A $\frac{\sqrt{5}}{3}$

Solution