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Question

The value of x+y+z if x2+y2+z2=18 and xy+yz+zx=9 is

A
9
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B
3
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C
6
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D
8
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Solution

The correct option is C 6
Squaring both sides
(x+y+z)2=x2+y2+z2+2(xy+yz+zx)
we can substitute given values
(x+y+z)2=18+(2×9)
(x+y+z)2=36
(x+y+z)=6

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