Question

The value of y in the given figure is

Answer 1

Sum of exterior angles $={360}^{\circ }$
$y+({180}^{\circ }-{60}^{\circ })+{70}^{\circ }+{130}^{\circ }={360}^{\circ }$
$y+{120}^{\circ }+{70}^{\circ }+{130}^{\circ }={360}^{\circ }$
$y={360}^{\circ }-{320}^{\circ }$
$y={40}^{\circ }$