The value of y increased by 12 is directly proportional to the value of x decreased by 6. If y=2 when x=8, find the value of x when y=16.
A
9
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B
10
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C
16
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D
20
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E
28
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Solution
The correct option is B10 As given y is directly proportional to x. i.e: y=kx for some constant k. According to question, if the value of y is increased by 12 is proportional to the value of x decreased by 6. i.e: y+12=k(x−6) Plugging x=8 and y=2 2+12=k(8−6) 14=2k ; k=7 The new equation is y+12=7(x−6) Plugging y=16 in above equation. ⇒16+12=7x−42 ⇒7x=70