The value(s) of a for which the roots of 2x2+(a2−1)x+a2+3a+4=0 are reciprocal to each other is/are
A
−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C−2 2x2+(a2+1)x+a2+3a+4=0
Comparing with ax2+bx+c=0
The roots are reciprocal when a=c, so we get ⇒a2+3a+4=2⇒a2+3a+2=0⇒(a+1)(a+2)=0⇒a=−1,−2