The correct option is C 74
Let α be the common root of both the given equations.
∴ 3α2+4kα+2=0 and2α2+3α−2=0
On solving by cross multiplication method we get:
α2−8k−6=−α−6−4=19−8k⇒α=109−8k ...(i)andα2=8k+68k−9 ...(ii)On simplifying (i) and (ii) we get:32k2−12k−77=0⇒32k2−56k+44k−77=0⇒8k(4k−7)+11(4k−7)=0⇒(8k+11)(4k−7)=0⇒k=−118, 74