Question

The value(s) of $p$ for which the quadratic equation $2x^2+px+8=0$ has equal roots is/are

• A. $8$
• B. $4$
• C. $-4$
• D. $-8$

Answer 1

Answer: (A), (D)

$-8$

$2x^2+px+8=0$ has equal roots.
$\Rightarrow D=0$
$\Rightarrow p^2-4\cdot 2\cdot 8=0\Rightarrow p^2=64\therefore p=\pm 8$