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Byju's Answer
Standard XII
Mathematics
Property 4
The values of...
Question
The values of
θ
∈
0
,
π
4
satisfying tan 5
θ
= cot 2
θ
are ______________.
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Solution
for
θ
∈
0
,
π
4
tan 5
θ
= cot 2
θ
i.e tan 5
θ =
1
tan
2
θ
⇒ tan 5
θ
tan2
θ
= 1 ...(1)
Since
tan (x + y) =
tan
x
+
tan
y
1
-
tan
x
tan
y
i.e tan(5
θ +
2
θ
) =
tan
5
θ
+
tan
2
θ
1
-
tan
5
θ
tan
2
θ
i.e tan 7
θ =
tan
5
θ
+
tan
2
θ
0
(from 1)
i.e tan 7
θ
is not defined
i.e tan 7
θ
=
tan
π
2
⇒ 7
θ =
n
π
+
π
2
i.e
θ =
n
π
7
+
π
14
If
θ
∈
0
,
π
4
,
θ
=
π
14
,
3
π
14
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