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Question

The values of a for which the quadratic equation 3x2+2(a2+1)x+(a23a+2)=0 has roots of opposite sign, is

A
a(1,2)
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B
a(2,)
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C
a(1,)
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D
a(2,3)
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Solution

The correct option is A a(1,2)
Given equation is
3x2+2(a2+1)x+(a23a+2)=0
It is a upward opening parabola
As the roots are of opposite sign, so
f(0)<0a23a+2<0(a1)(a2)<0a(1,2)

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