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Byju's Answer

Standard XII

Physics

Convection

The values of...

Question

The values of critical pressures $(P_{c})$ and critical temperature $(T_{c})$ for $O_{2}, C l_{2}, H_{2}$ and he are given below The gas which has smallest value of van der Waal's constant 'b' is:

Name of the gas $P_{c}$
$(N m^{- 2})$
$T_{c}$
(K)
$O_{2}$ $5 \times 10^{\circ}$ 153
$C l_{2}$ $8 \times 10^{\circ}$ 412
$H_{2}$ $1 \times 10^{\circ}$ 33.9
$H_{e}$ $2 \times 10^{\circ}$ 5.12

O_{2}

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C l_{2}

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H_{2}

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H_{e}

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Solution

The correct option is D $H_{e}$
$T_{c} = \frac{8 a}{27 R b}$ and $P_{c} = \frac{a}{27 b^{2}}$

$\frac{T_{c}}{P_{c}} = \frac{8 B}{R}$

Therefore $b = \frac{R}{8} \frac{T_{c}}{P_{c}}$

So He gas has smallest value of 'b' as it has lowest value of $T_{c}$

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Similar questions

Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$

From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first

(a) $H_{2}, H e, O_{2}, N_{2}$ (b) $H e, O_{2}, H_{2}, N_{2}$

Q. Gases

H_{2} H e O_{2} N_{2}

Critical temperature(K) 33.2 5.3 154.3 126

From the above data what whould be the order of liquefaction of these gases?
Start writing the order from the gas liquefying first.

Which of the following statements on critical constants of gases are correct?

I : Larger the $\frac{T_{c}}{P_{c}}$ value of a gas, larger would be the excluded volume.

II : Critical temperature ( $T_{c}$ ) of a gas is greater than its Boyle's temperature ( $T_{B}$ ).

III : At the critical point in the Van der Walls gas isotherm.

$⟮ \frac{d P}{d V_{m}} ⟯ T_{c} = 0$

Q. The Van der waal's constant 'a' for gases

C H_{4}, N_{2}, N H_{3}

and

O_{2}

are 2.25, 1.39, 4.17 and 1.3

L^{2} a t m m o l^{- 2}

respectively. The gas which shows highest critical temperature is:

Q. Which of the following statements on critical constants of gases are correct?

I :

Larger the

T_{c} / p_{c}

value of a gas, larger would be the excluded volume.

I I :

Critical temperature

(T_{c})

of a gas is greater than its Boyles's temperature

(T_{b})

I I I :

At the critical point in the van der Waals' gas isotherm.

(\frac{δ p}{δ V_{m}}) T_{c} = 0

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Name of the gas	$P_{c}$ $(N m^{- 2})$	$T_{c}$ (K)
$O_{2}$	$5 \times 10^{\circ}$	153
$C l_{2}$	$8 \times 10^{\circ}$	412
$H_{2}$	$1 \times 10^{\circ}$	33.9
$H_{e}$	$2 \times 10^{\circ}$	5.12

The values of critical pressures (Pc) and critical temperature (Tc) for O2,Cl2,H2 and he are given below The gas which has smallest value of van der Waal's constant 'b' is:Name of the gas Pc(Nm−2)Tc(K)O25×10∘153Cl28×10∘412H21×10∘33.9He2×10∘5.12

The correct option is D HeTc=8a27Rb and Pc=a27b2TcPc=8BRTherefore b=R8TcPcSo He gas has smallest value of 'b' as it has lowest value of Tc

The correct option is D $H_{e}$
$T_{c} = \frac{8 a}{27 R b}$ and $P_{c} = \frac{a}{27 b^{2}}$

$\frac{T_{c}}{P_{c}} = \frac{8 B}{R}$

Therefore $b = \frac{R}{8} \frac{T_{c}}{P_{c}}$

So He gas has smallest value of 'b' as it has lowest value of $T_{c}$