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Question

The values of k for which the function f(x)=kx39x2+9x+3 may be increasing on R are

A
k>3
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B
k<3
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C
k3
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D
None of these
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Solution

The correct option is B k>3
We have, f(x)=kx39x2+9x+3
f(x)=3kx218x+9
Since f(x) is increasing on R, therefore,
f(x)>0xR
3kx218x+9>0xR
kx26x+3>0xR
k>03612k<0
[ax2+bx+c>0xRa>0 and D<0]
k>3
Hence, f(x) is increasing on R, if k>3.

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