Question

The values of Λ0eq for NH4Cl, NaOH and NaCl are 149.74, 248.1 and 126.4 ohm−1 cm2 eq−1 respectively. The value of Λ0eq(NH4OH) is :

A
371.44
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B
271.44
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C
171.44
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D
Cannot be calculated from the data given
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Solution

The correct option is B 271.44Kohlrausch law: At infinite dilution, when all the interionic effects disappear and dissociation of electrolyte is complete, each ion makes a definite contribution towards equivalent conductance of the electrolyte irrespective of the nature of the ion with which it is associated. Kohlrausch law of independent migration of ions: Λ0eq=λ0eq++λ0eq− λ0eq+→Limiting equivalent conductivities of cation λ0eq−→Limiting equivalent conductivities of anion Λ0NH4Cl=λ0eq(NH+4)+λ0eq(Cl−) Λ0eqNaOH=λ0eq(Na+)+λ0eq(OH−) Λ0eqNaCl=λ0eq(Na+)+λ0eq(Cl−) Thus, Λ0eq(NH4OH)=λ0eq(NH+4)+λ0eq(Cl−)+λ0eq(Na+)+λ0eq(OH−)−[λ0eq(Na+)+λ0eq(Cl−)] ∴ Λ0eq(NH4OH)=λ0eq(NH4Cl)+λ0eq(NaOH)−λ0eq(NaCl) Λ0eq(NH4OH)=149.74+248.1−126.4 Λ0eq(NH4OH)=271.44 ohm−1 cm2 eq−1

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