The values of ${log}_{5} 125 + {log}_{2} 2$

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Solution

The correct option is A 4
${log}_{5} 125 + {log}_{2} 2 = {log}_{5} 5^{3} + {log}_{2} 2 = 3 + 1 = 4$

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Similar questions

{log}_{5} 125

4 + 2 (1 + 2) log 2 + \frac{2 (1 + 2^{2})}{2!} {(log 2)}^{2} + \frac{2 (1 + 2^{3})}{3!} {(log 2)}^{3} + \dots

4 + 2 (1 + 2) log 2 + \frac{2 (1 + 2^{2})}{2!} {(log 2)}^{2} + \frac{2 (1 + 2^{3})}{3!} {(log 2)}^{3} + . . . .

2 {log}_{4} (4 - x) = 4 - {log}_{2} (2 + x)

{log}_{5} 125 + {log}_{6} 216

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