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Question

The values of parameter a such that the line (log2(1+5aa2))x5y(a25)=0 is a normal to the curve xy=1, may be in the interval


A
(,0)
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B
(5,)
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C
(0,5)
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D
(,0)(5,)
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Solution

The correct option is C (0,5)
For xy=1dydx=1x2
Slope of normal to xy=1 for x2 is > 0  (x0)
Slope of line (given) =log2(1+5aa2)5>0
So 1+5aa2>1
a25a<0 hence aϵ(0,5)
 

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