The values of sin105° is equal to

cos45°

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sin45°

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cos15°

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sin60°

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Solution

The correct option is C
cos15°

sin105° = sin(90° + 15°) = cos15°

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Similar questions

sin 105^{\circ} . sin 75^{\circ} i s

\frac{cos 105^{\circ} + sin 105^{\circ}}{cos 105^{\circ} - sin 105^{\circ}}

\frac{cos 105^{\circ} + sin 105^{\circ}}{cos 105^{\circ} - sin 105^{\circ}}

sin105° + cos105° is equal to:

What is the value of sin 105^o + sin 75^o?

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