Question

The values of slope and intercept in the graph of Freundlich adsorption isotherm at ${25}^{o}C$ temperature are $0.5$ and $0.4771$ respectively. What will be the proportion of adsorption at $4$ bar pressure?

• A. $12$
• B. $6$
• C. $24$
• D. $3$

Answer 1

Answer: (B)

$6$

The relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature can be expressed by the following equation : $\frac{x}{m}=k.p^{1/n}$

By taking log of this relation we get $log\frac{x}{m}=logk+\frac{1}{n}logp$

hence here slope $=\frac{1}{n}=0.5$ and intercept $=logk=0.4771$

$⟹k=3$

$\therefore \frac{x}{m}=3\times 4^{\left(0.5\right)}=6$

Hence, option $B$ is correct.