The values of the digits A and B in the given multiplication are
A B
x 6
____
2 8 8
The value of B can be either 3 or 8 because 3×6=18 and 8×6=48.
If we take B = 3, we can write
6×A+1=28⇒ 6A=28−1⇒A=276=92
But A must be a single digit whole number, and hence we reject the possibility of B being 3.
Now, if B = 8, then
6×8=48.
⇒6×A+4=28⇒6×4+4=28
So, A = 4 and B = 8