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Byju's Answer
Standard XII
Mathematics
General Solution of sin theta = sin alpha
The values of...
Question
The values of '
θ
' satisfying the equation
cos
θ
.
cos
(
π
3
+
θ
)
.
cos
(
π
3
−
θ
)
=
1
4
is
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Solution
As we know that
cos
(
A
+
B
)
cos
(
A
−
B
)
=
cos
2
B
−
sin
2
A
Given
cos
(
π
3
+
θ
)
cos
(
π
3
−
θ
)
=
1
4
⟹
cos
2
θ
−
sin
2
π
3
=
1
4
⟹
cos
2
θ
=
1
4
+
3
4
⟹
cos
2
θ
=
1
⟹
θ
=
n
π
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General Solution of sin theta = sin alpha
Standard XII Mathematics
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