You visited us 1 times! Enjoying our articles? Unlock Full Access!

Points of Discontinuity

The values of...

Question

The values of x and y for which the numbers 3+i $x^{2}$ y and $x^{2}$ +y+4i are conjugate complex are

(-2,-1) or (2,-1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1,-2) or (-2,1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1,2) or (-1,-2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
(-2,-1) or (2,-1)

According to condition, 3-i $x^{2}$ y = $x^{2}$ + y + 4i

⇒ $x^{2}$ + y = 3 And $x^{2}$ y = -4 ⇒ x = ±2, y = -1

⇒ (x,y) = (2,-1) or (-2,-1)

Suggest Corrections

Similar questions

- 3 + i x^{2} y

x^{2} + y + 4 i

x

y

- 3 + i x^{2} y

x^{2} + y + 4 i

x

y

- 3 + i x^{2} y

x^{2} + y - 4 i

i = \sqrt{- 1}

The values of x and y for which the numbers 3+i $x^{2}$ y and $x^{2}$ +y+4i are conjugate complex can be

Find the value of $x^{2} + y^{2}$ for which the complex numbers $- 3 - i x^{2} y$ and $x^{2} + y + 4 i$ are equal , where x and y are real numbers .

Join BYJU'S Learning Program