The values of x and y in the given figure are respectively
40∘ and 25∘
∠A+∠C=180∘ [Sum of opposite angles of a cyclic quadrilateral is 180∘]
⇒2x+4+4y−4=180∘
⇒2x+4y=180∘
⇒x+2y=90∘ .... (i)
∠B+∠D=180∘ [Sum of opposite angles of a cyclic quadrilateral is 180∘]
⇒x+10+5y+5=180∘
⇒x+5y=165∘ .... (ii)
On substracting (i) from (ii), we get
3y=75⇒y=25∘
Also, x=40∘