The values of x and y satisfying the two equation $32 x + 33 y = 31$ , $33 x + 32 y = 34$ respectively will be

-1,2

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2,-1

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0,0

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2,3

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Solution

The correct option is B 2,-1
32x + 33y = 21 ......(i)
33x + 32y = 34 .....(ii)
Subtracting equation (ii) from (i) we get
-x+y=-3
or y=x-3 .....(iii)
Substituting the value of y in equation (i), we get
32x + 33(x-3) = 31
or 32x + 33x - 99 = 31
or 65x = 130
or x=2
Then from equation (iii)
y=2-3=-1

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32 x + 33 y = 31

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