Question

The values of x and y satisfying the two equations $32x+33y=31$, $33x+32y=34$ respectively will be

• A. $-1,2$
• B. $2,-1$
• C. $0,0$
• D. $2,3$

Answer 1

The correct option is B $2,-1$

Multiplying $32x+33y=31$ with $33$, we get $1056x+1089y=1023$ ---- (1)

Multiplying $33x+32y=34$ with $32$, we get $1056x+1024y=1088$ ---- (2)
Subtracting (2) from (1),
$1056x+1089y-1056x-1024y=1023-1088$
$65y=-65$
$y=-1$

Substituting $y=-1$ in $32x+33y=31$ , we get $ 32x - 33 = 31

$32x=64$

$x=2$