949
You visited us
949
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XI
Mathematics
Fundamental Laws of Logarithms
The values of...
Question
The values of
x
for which
log
3
(
x
+
2
)
(
x
+
4
)
+
log
1
/
3
(
x
+
2
)
<
1
2
log
√
3
7
holds, is
A
−
4
<
x
<
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x
<
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x
>
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−
2
<
x
<
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is
D
−
2
<
x
<
3
Clearly,
(
x
+
2
)
(
x
+
4
)
>
0
and
x
+
2
>
0
⇒
x
>
−
2
⋯
(
1
)
Now,
log
3
(
x
+
2
)
(
x
+
4
)
+
log
1
/
3
(
x
+
2
)
<
1
2
log
√
3
7
⇒
log
3
(
x
+
2
)
(
x
+
4
)
x
+
2
<
log
3
7
⇒
log
3
(
x
+
4
)
<
log
3
7
⇒
x
+
4
<
7
⇒
x
<
3
⋯
(
2
)
From
(
1
)
and
(
2
)
,
−
2
<
x
<
3
Suggest Corrections
0
Similar questions
Q.
Solve the inequality:
log
3
(
x
+
2
)
(
x
+
4
)
+
log
1
/
3
(
x
+
2
)
<
1
2
log
√
3
7
Q.
Solution set of the inequality
log
3
(
x
+
2
)
(
x
+
4
)
+
log
1
3
(
x
+
2
)
<
1
2
log
√
3
7
is -
Q.
The solution set of the inequality
log
3
(
(
x
+
2
)
(
x
+
4
)
)
+
log
1
/
3
(
x
+
2
)
<
1
2
log
√
3
7
is
Q.
The complete solution set of the inequality
log
3
(
x
+
2
)
(
x
+
4
)
+
log
1
/
3
(
x
+
2
)
<
1
2
log
√
3
7
is equal to
Q.
The value of
x
for the inequation
(
l
o
g
(
1
/
2
)
x
≥
l
o
g
(
1
/
3
)
x
)
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Explore more
Fundamental Laws of Logarithms
Standard XI Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app