The values of x for which the angle between the vectors a=xi−3j−k and b=2xi+xj−k is acute, and the angle between the vector b and the axis of ordinates is obtuse, are
A
1,2
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B
−2,−3
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C
all x<0
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D
all x>0
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Solution
The correct options are B−2,−3 C all x<0 According to the given conditions, a⋅b>0 and b⋅c<0, where c=(0,1,0) as c is on the ordinate axis which means x and z are 0 Thus, 2x2−3x+1>0⇒(x−1)(2x−1)>0⇒x∈(−∞,1/2)∪(1,∞) and x<0 Combining both we get x<0
Hence, x<0 is correct. Furthermore, -2 and -3 are both <0 which means it is correct too.