The values of x for which the function f(x)=x2+x+1x2−7x+12 is not defined, is
A
{3,4}
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B
{3,−4}
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C
{−3,−4}
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D
the function is defined everywhere
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Solution
The correct option is A{3,4} f(x)=x2+x+1x2−7x+12 It is a rational function, so the function is not defined when the denominator is equal to zero. x2−7x+12=0⇒(x−3)(x−4)=0⇒x=3,4