The values of $x$ for which $x^{2} + (2 - 5 b) x - 10 b = 0$ are

- 2, 5 b

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2, - 5 b

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2 b, 5

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- 2 b, 5

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Solution

The correct option is B $- 2, 5 b$
Given equation is:
$x^{2} + (2 - 5 b) - 10 b = 0$
$x^{2} + 2 x - 5 b x - 10 b = 0$
$x (x + 2) - 5 b (x + 2) = 0$
$(x - 5 b) (x + 2) = 0$
$∴ x = 5 b$ and $x = - 2$

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