The values of x satisfying $l o g_{3} (x^{2} + 4 x + 12) = 2 a r e$

2,-4

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1, -3

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-1, 3

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-1, -3

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Solution

The correct option is D
-1, -3

The given equation is $l o g_{3} (x^{2} + 4 x + 12) = 2 \Rightarrow x^{2} + 4 x + 12 = 3^{2} = 9 \Rightarrow x^{2} + 4 x + 3 = 0 \Rightarrow (x + 1) (x + 3) = 0 \Rightarrow x = - 1, - 3$

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Similar questions

(x^{2} + 4 x + 12) = 2

x^{{log}_{3} x^{2} + ({log}_{3} x)^{2} - 10} = \frac{1}{x^{2}}

x

x

{| x - 1 |}^{{log}_{3} x^{2} - 2 {log}_{x} 9} = (x - 1)^{7}

The set of real values of x satisfying the equation
${| x - 1 |}^{l o g_{3} (x^{2}) - 2 l o g_{x} (9)} = (x - 1)^{7}$
is

x

{| x - 1 |}^{{log}_{3} x^{2} - 2 {log}_{9} x} = (x - 1)^{7}

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