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Question

The values of x satisfying the equation 52x5x+3+125=5x are :

A
0 and 2
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B
1 and 3
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C
0 and 3
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D
0 and 3
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Solution

The correct option is C 0 and 3
Given equation is: 52x5x+3+125=5x
Let 5x=t
Hence, t253.t+125=t
t2126t+125=0
t2126tt+125=0
t(t125)1(t125)=0
(t1)(t125)=0
t=1 and t=125
Hence, 5x=1=50 or 5x=125=53
Therefore, x=0 or x=3

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