CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The values of x satisfying the equation 52x5x+3+125=5x are :

A
0 and 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 and 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0 and 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0 and 3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 0 and 3
Given equation is: 52x5x+3+125=5x
Let 5x=t
Hence, t253.t+125=t
t2126t+125=0
t2126tt+125=0
t(t125)1(t125)=0
(t1)(t125)=0
t=1 and t=125
Hence, 5x=1=50 or 5x=125=53
Therefore, x=0 or x=3

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon