Question

The van dar Waal's constant for four gases $P,Q,R$ and $S$ are $4.17,3.59,6.71$ and $3.8atm{L}^{2}mo{l}^{-2}$.

Therefore, the ascending order of their liquification is

• A. $R<P<S<Q$
• B. $Q<S<R<P$
• C. $Q<S<P<R$
• D. $R<P<Q<S$

Answer 1

The correct option is C $Q<S<P<R$

As the value of van der Waal's constant increases, ease of liquification of a gas also increases. The ascending order of van der Waal's constants for gases $P,Q,R,S$ is as
$\underset{\left(Q\right)}{3.59}<\underset{\left(S\right)}{3.8}<\underset{\left(P\right)}{4.17}<\underset{\left(R\right)}{6.71}$
Thus, the order of ease of liquification is
$Q<S<P<R$.